A copper wire when bent in the form of a square encloses an area of 121 sqcm.If the same wire is bent into the form of a circle.Find the area of the circle.
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hiii!!!
here's ur answer...
the same wire in the form of square is bent into circle, then :-
perimeter of square = circumference of circle
given area of the square = 121cm²
therefore side² = 121cm²
==> side = √121
==> side = 11cm
VERIFICATION:-
area of the square = side²
= 11 × 11
= 121cm²
hence verified
thus the side of the square is 11cm.
perimeter of the square = side × 4
= 11 × 4
= 44cm
therefore circumference of the circle is also 44cm.
==> 2πr = 44cm
==> 2 × 22/7 × r = 44cm
==> 44/7 × r = 44cm
==> r = 44/1×7/44
==> r = 7cm
VERIFICATION:-
circumference of the circle = 2πr
= 2 × 22/7 × 7
= 44cm
hence verified
thus the radius of the circle is 7cm.
now,
area of the circle = πr²
= 22/7 × 7 × 7
= 22 × 7
= 154cm²
hope this helps..!!
here's ur answer...
the same wire in the form of square is bent into circle, then :-
perimeter of square = circumference of circle
given area of the square = 121cm²
therefore side² = 121cm²
==> side = √121
==> side = 11cm
VERIFICATION:-
area of the square = side²
= 11 × 11
= 121cm²
hence verified
thus the side of the square is 11cm.
perimeter of the square = side × 4
= 11 × 4
= 44cm
therefore circumference of the circle is also 44cm.
==> 2πr = 44cm
==> 2 × 22/7 × r = 44cm
==> 44/7 × r = 44cm
==> r = 44/1×7/44
==> r = 7cm
VERIFICATION:-
circumference of the circle = 2πr
= 2 × 22/7 × 7
= 44cm
hence verified
thus the radius of the circle is 7cm.
now,
area of the circle = πr²
= 22/7 × 7 × 7
= 22 × 7
= 154cm²
hope this helps..!!
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