Question

A copper wire when bent in the form of a square encloses an area of 484cm2. The same wire is now bent in the form of a circle .Find the area enclosed by the circle..

Answer 1

area of square= 484cm2,

Area of square = side2,

thus, side = 4841/2cm =

22cm.

length of wire is same,

thus perimeter of square = circumference of circle,

=> 4*side= 2*pi*r => 88 = 44*r/7

=> r= 14 ,area enclsd. by circle = 22/7*142

=616cm2...

hope it help!! make as brilliancy..

Answer 2

Let each side of a square be x cm and radius of the circle be r cm

Area of the square = $\sf{{484cm}^{2}}$

$\therefore$ $\sf{ {x}^{2} = 484 = x = 22cm}$

$\therefore$ Perimeter of the square

= 22 × 4 = 88cm = Length of the wire

= Circumference of the circle, when the same wire is bent in the form of a circle

= 2πr = 88

= $\sf{r=\frac{44}{π}}$

$\therefore$ Area of the circle =

= $\sf{\pi \times \frac{44}{\pi} \times \frac{44}{\pi} = \frac{44}{22} \times 7 \times 44}$

= $\sf{ {616cm}^{2}}$