Question

A copper wire when bent in the form of an equilateral triangle has area 121root3cm square.
If the same wire is bent into the form of a circle, find the area enclosed by the wire.​

Answer 1

Step-by-step explanation:

Let side of eq.triangle be = a cm

Area of eq. triangle = √3a²/4 = 121√3 cm²

= a² = 484

= a = 22 cm

Length of wire = Perimeter of triangle

Length of wire = 3 * 22

Length of wire = 66 cm = Circumference of the new circle

66 = 2*22/7*r ( radius of circle be r cm)

21/2 cm = r

Area enclosed by the circle = 22/7*21/2*21/2

Area enclosed = 693 cm²

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