a copper wire when bent in the from of an equilateral triangle encloses an area of 25√3cm2 if the same wire is bent into the form of a square,find the area of the square
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as w know that
area of equilateral triangle = root 3 /4 × side ^2
25root 3 = root3 /4 × side^2
side^2 = 25 root3 × 4/ root 3
side^2 = 25 × 4
side = 10 cm
perimeter of triangle = 10 × 3
= 30 cm
so lenght of wire is 30 cm
If it is bend into square
the side = 30/4
= 7 . 5
area of square = side ^2
= 7.5^2
= 56.25 cm^2
area of equilateral triangle = root 3 /4 × side ^2
25root 3 = root3 /4 × side^2
side^2 = 25 root3 × 4/ root 3
side^2 = 25 × 4
side = 10 cm
perimeter of triangle = 10 × 3
= 30 cm
so lenght of wire is 30 cm
If it is bend into square
the side = 30/4
= 7 . 5
area of square = side ^2
= 7.5^2
= 56.25 cm^2
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