Physics, asked by mukimani35, 7 hours ago

-
A copper wire when cut 2% shorter, then new
resistance is R, but when the original wire is
stretched by 2%, the new resistance is R, then
R₂-R,
value of
RA
is approximately
(13
(2) 0.5 x 10-2
(3) 2 x 10-2
(4) 4 x 10-2

Answers

Answered by achu519
3

Answer:

sorry I don't know the answer

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