Question

A copper with whose diameter is 0.16 cm carries a steady current of 10 A. What is the current density of

the wire? Also calculate the drift velocity of the electrons in copper.

Solution [ = 497.6 104 A/m2

, vd = 3.6X10-4m/s]​

Answer 1

Answer:

r=0.16/2

r=0.08cm

A=πr^2

A=0.02cm^2

j=I/A

j=10/0.02

j=500A/cm^2

,n=I/e

10/1.6*10^-19

6.25*10^-19

I=neAVd

Vd=I/neA

Vd=10/6.25*10^-19*1.6*10^-19*0.02*10^-2

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