A cord 80 cm long is stretched by a load of 8 kgf. The mass per unit length of the
cord is 4 x 10-5 kg m-!. Find:
iSpeed of the transverse wave in the cord, and
(ii) Fundamental frequency of vibration.
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Explanation:
Given A cord 80 cm long is stretched by a load of 8 kgf. The mass per unit length of the cord is 4 x 10-5 kg m-!. Find: (i) Speed of the transverse wave in the cord, and (ii) Fundamental frequency of vibration.
- We know that velocity v = √T / m
- T = F = 8 x 9.8
- m = 4 x 10^-5
- Now v = √8 x 9.8 / 4 x 10^-5
- Or v = √19.6 x 10^5
- Or v = 1400 m/s is the speed of transverse wave.
- Now frequency ν = 1 / 2L √T / m
- = 1 / 2 x 0.8 √1400
- = 14,000 / 2 x 8
- = 7000 / 8
- = 875 hertz
Fundamental frequency of vibration is 875 hertz.
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