Question

A cord is wrapped around the rim of a cylinder that has a mass of 10 kg and a
radius of 30 cm. If the rope is pulled with a force of 60 N, what is the angular
acceleration of the cylinder?​

Answer 1

Answer:

A rope of negligible mass is wound round a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N? What is the linear acceleration of the rope Assume that there is no slipping.

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VIDEO EXPLANATION

ANSWER

The moment of inertia of the hollow cylinder about its geometric axis:

I=mr

2

=3×0.4

2

kgm

2

The Torque developed is given by:

τ=rF=0.4×30Nm=12Nm

We know that the relation between the torque and angular acceleration is:

τ=Iα

⟹α=25rads

−2

Thus linear acceleration(a)=rα=0.4×25m/s

2

=10m/s

2

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Answer 2

Explanation:

F=ma

• in rotational motion a=r

a

$a = r \alpha$

$f = ma$

$f = mr \alpha$

$\alpha = f \div mr$

now putting values