A cord PQ of a circle of radius 10cm makes an angle of 60. At the centre of the circle find the area of the major and the minor segment
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Answer:
Step-by-step explanation:
Radius=10cm
60° angle
Proof: area of major segment= theta/360πr^2-r^2/2 sin theta
= 60/360x22/7x10x10-10x10x1/2x√3
= 11x100/21 -50√3
=1100/21-50√3
=52•3-50√3 cm^2
I hope this is helpful
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