Question

A cord PQ of a circle of radius 10cm makes an angle of 60. At the centre of the circle find the area of minor segment​

Answer 1

Answer:

Step-by-step explanation:

Angle (a) is 60 degree

Area of minor segment = a/360*pi*r^2 + r^2*sin(a/2)*cos(a/2)

60/360 * 3.14 * 10^2 + 10^2*sin30*cos30 = 95.63