Question

A=cos^2thita +sin^4thita​

Answer 1

Answer:

Step-by-step explanation:A=cos  

2

θ+sin  

4

θ

A=cos  

2

θ+sin  

2

θsin  

2

θ≤cos  

2

θ+sin  

2

θ

A=cos  

2

θ+sin  

2

θsin  

2

θ≤1                                  (sin  

2

θ+cos  

2

θ=1).       ----(1)

or A=cos  

2

θ+sin  

4

θ

   A=(1−sin  

2

θ)+sin  

4

θ

   A=(sin  

2

θ)  

2

+(  

2

1

​  

)  

2

−2×  

2

1

​  

×sin  

2

θ+(1−  

4

1

​  

)

   A=(sin  

2

θ−  

2

1

​  

)  

2

+  

4

3

​  

≥  

4

3

​  

           ----------(2)

From equation 1 and 2,

4

3

​  

≤A≤1

Answer 2

Answer:

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