Math, asked by wwwmufaiz, 7 months ago

(a) cos A. sin (B-C) + cos B · sin (C-A)
+ cos C. sin (A - B) = 0

Answers

Answered by sp6559568

1

Answer:

Sin(A-B)/cosA.cosB + sin (B-C)/cosB.cosC + sin (C-A)/cosC.cosA =0. ... sin(A−B)cosAcosB +sin(B−C)cosBcosC+sin(C−A)cosCcosA.

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