Question

a.cosA+b.sinA=p and a sin A -n cosA=a than prove that a×a+b×b=p×p+q×a

Answer 1

cosec A+cot A=p1/sinA  + cosA/sinA = p1+cosA = psinASquaring both the sides(1+cosA)^2 = p^2 (sinA)^2(1+cosA)^2 = p^2 (1-(cos)^2)(1+cosA)^2 = p^2 (1-(cos)) (1+cosA)1+cosA = p^2 (1-cosA)cosA = (p^2-1)/(p^2+1)Hence proved
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