a(cosC-cosB)=2(b-c)cos^2 A/2
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Let, a = k sinA, b = k sinB, c = k sinC
RHS
⇒b-c/a cos A/2
⇒ (ksinB - ksinC/k sinA )cos A/2
⇒ {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2
⇒[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA
⇒ [SinA* sinB-C/2] / sinA
⇒ Sin B-C/2 = LHS
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