Math, asked by paramdholakia90757, 8 months ago

a(cosC-cosB) = 2(b-c)cos
please prove it with full detail
...Jai Hind..
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Answers

Answered by RiShAbKhEr
1

Step-by-step explanation:

a = k sinA, b = k sinB, c = k sinC

RHS

b-c/a cos A/2

= (ksinB - ksinC/k sinA )cos A/2

= {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2

=[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA

= [SinA* sinB-C/2] / sinA

= Sin B-C/2

= LHS

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