a
cosecA + sec A
cos2A - sin2A
sin Ascos 2A - COSA-S102A
Answers
Answered by
4
Answer:
Your answer attached in the photo
Attachments:
Answered by
1
Answer:
cos²A-sin²A/sinAcos²A-cosAsin²A
= (cosA+sinA)(cosA-sinA)/sinAcosA(cosA-sinA)
= cosA+sinA/sinAcosA
=cosecA+secA
ᏢᏒᎾᎾᏉᎬᎠ
Similar questions