Math, asked by barsaoli4, 5 months ago

a
cosecA + sec A
cos2A - sin2A
sin Ascos 2A - COSA-S102A
 \frac{cos ^{2}a - sin ^{2}a  }{sina \times cos ^{2}a - cosa \times sin^{2}a }  = coseca + sec

Answers

Answered by sandy1816
4

Answer:

Your answer attached in the photo

Attachments:
Answered by samimpapa354
1

Answer:

cos²A-sin²A/sinAcos²A-cosAsin²A

= (cosA+sinA)(cosA-sinA)/sinAcosA(cosA-sinA)

= cosA+sinA/sinAcosA

=cosecA+secA

ᏢᏒᎾᎾᏉᎬᎠ

Similar questions