Question

A cosmonaut is orbiting earth in a spacecraft at an altitude h = 630 km with a speed of 8 km/s. If the
radius of the earth is 6400 km, the acceleration of the cosmohaut is
(1) 9.10 m/s
(2) 9.80 m/s
(3) 10.0 m/s
(4) 9.88 m​

Answer 1

Answer: (a)

Explanation:

Given, v=8 kms−1=8000 ms^−1,  

r = (6400 + 630) km = (6400 + 630) × 1000 m  

a = v^2/r  

a = (8000)^2 / (6400+630)×1000  

  = 9.10 ms^−2

Answer 2

(a) The acceleration of the cosmonaut is $a = 9.10 m/s^2$.

Explanation:

As the cosmonaut is orbiting the earth, so the acceleration of the cosmonaut is given as

$a=\frac{v^2}{r}$

Here  v is the velocity of the cosmonaut and r is the radius, r = R(radius of earth) +h(altitude).

Given  $v=8km/s$  and $r=6400km+630km=7030km$.

Substitute the given values, we get

$a=\frac{(8000m/s)^2}{7030\times10^3m}$

$a = 9.10 m/s^2$

Thus, the acceleration of the cosmonaut is $a = 9.10 m/s^2$

#Learn More: acceleration.

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