a cot theta+ b cosec theta =P
b cot theta + a cosec theta
= Q
then find p² - Q²
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GIVEN :-
a cot theta+ b cosec theta =P
a cot theta+ b cosec theta =Pb cot theta + a cosec theta = Q
TO FIND:- P² - Q²
SOLUTION:-
GIVEN AS, A COT THETA + B COSEC THETA = P
B COT THETA + A COSEC THETA = Q
NOW P² =(A COT THETA + B COSEC THETA)²
P² = A²COT²THETA + B²COSEC²THETA ...............1
Q² = B²COT²THETA + A²COSEC²THETA................2
SO P² - Q² = (A²COT²THETA + B²COSEC²THETA + 2ABCOT THETA COSEC THETA) - (B²COT²THETA + A²COSEC²THETA 2ABCOT THETA COSEC THETA)
P² - Q² = COT²THETA ( A² - B² ) - COSEC²THETA( A² - B² )
P² - Q² = ( A² - B² ) [ COT²THETA - COSEC²THETA]
SO , P² - Q² = ( A² - B² )
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