a cottage industry produce a certain number of pottery articles in a day it observed on a particular day that the cost of production of each article (in rupee) was 3 more than twice the number of article produced on that day if total cost of production on that day was rupee 90 find the number of articles produced and cost of each article
Answers
Answer:
15 rupees
Step-by-step explanation:
We know that
Total cost of production = Number of articles produced × Cost of article
Given total cost of production =Rs.90
and
Cost of production of each article (in rupees) was 3 more than twice and number of articles produced on that day
Let the number of articles =x
Hence, Cost of article =2x+3
Now,
Total cost of production = Number of articles produced × Cost of article
90=x(2x+3)
2x
2
+3x−90=0
2x
2
+15x−12x−90=0
x(2x+15)−6(2x+15)=0
(x−6)(2x+15)=0
x=6,
2
−15
But x cannot be negative as number of articles is not negative
Hence, x=6
∴ Number of articles =6
And Cost of article =2x+3
=2(6)+3
=12+3
=Rs.15
Answer:
Rs.15
Step-by-step explanation:
Let the number of pottery articles produced by a cottage industry be 'x'
Given the cost of production of each article ( in rupees) was 3 more than twice the number of articles produced on that day
• price of each article = 2x+3
total cost of each article = rs.90
i.e. x (2x+3)=90
2x^2+3x=90
2x^2+3x-90=0
2x^2+15x-12x-90=0
x (2x+15)-6 (2x+15)=0
(2x+15) (x-6) =0
2x+15=0
x= -15/2
and
x-6=0
x=6
number of articles never be negative so x is not equal to -15/2
price of article=2x+3 = 2 (6)+3 = 12+3= 15
price of article= rs.15