A cottage industry produces a certain number of potteries in a day. It was found that the cost of production of each article 5 more than twice the number of potteries produced in a day. If the cost of production on that day was Rs 168 ,find the number of potteries produced.
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Let the number of articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
The total cost of production = Total quantity produced x cost of one article
It is given that the total cost of production is Rs 90.
∴ x (2x + 3) = 90
⇒ 2x2 + 3x = 90
⇒ 2x2 + 3x – 90 = 0
⇒ 2x2 +15x - 12x-90 =0
⇒ x (2x + 15) - 6(2x + 15) = 0
⇒(2x + 15) (x - 6) = 0
Either 2x + 15 = 0 or x − 6 = 0,
i.e., x = or x = 6
As the number of articles produced can only be a positive integer,
Therefore, x can only be 6.
Hence, the number of articles produced = 6
Cost of each article = 2 × 6 + 3
= 12 + 3= Rs 15
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