Math, asked by rajashrichavan819, 9 months ago

A cottage industry produces a certain number of potteries in a day. It was found that the cost of production of each article 5 more than twice the number of potteries produced in a day. If the cost of production on that day was Rs 168 ,find the number of potteries produced.

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Answered by TheWorker
95

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Answered by nidinmadhav107
4

Let the number of articles produced be x.

Therefore, cost of production of each article = Rs (2x + 3)

The total cost of production = Total quantity produced x cost of one article

It is given that the total cost of production is Rs 90.

∴ x (2x + 3) = 90

⇒ 2x2 + 3x = 90  

⇒ 2x2 + 3x – 90 = 0

⇒ 2x2 +15x - 12x-90 =0

⇒ x (2x + 15) - 6(2x + 15) = 0

⇒(2x + 15) (x - 6) = 0

Either 2x + 15 = 0 or x − 6 = 0,

i.e., x = or x = 6

As the number of articles produced can only be a positive integer,

Therefore, x can only be 6.

Hence, the number of articles produced = 6

Cost of each article = 2 × 6 + 3

= 12 + 3= Rs 15

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