Math, asked by swethavsky, 10 months ago

A cottage industry produces a certain number of pottery articles in a day. It was
observed on a particular day that the cost of production of each article (in rupees)
was 3 more than twice the number of articles produced on that day. If the total
cost of production on that day was Rs 90, find the number of articles produced
and the cost of each article.

Answers

Answered by Anonymous
0

Step-by-step explanation:

Let the number of articles be x

Twice the number of articles be 2x

The cost is 3 rupees more when twice the number of articles are produced in a particular day be 2x+3.

x(2x+3)=90

2x²+3x =90

2x²+12x-90=0

2x²-12x+15x-90 =0

2x(x-6) + 15( x-6) = 0

2x + 15 = 0. x-6=0

2x = -15. x= 6

x= -15/2

Taking the positive value

The number of articles x=6

the cost is 2x+3

2(6)+3

12+ 3

15..

I hope it will help you!

Answered by Anonymous
0

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.

Attachments:
Similar questions