Math, asked by modi04092, 10 months ago

A cottage industry produces a certain number of pottery articles in a

day. It was observed on a particular day that the cost of production of

each article (in rupees) was 3 more than twice the number of articles

produced on that day. If the total cost of production on that day was `

90, find the number of articles produced and the cost of each article.​

Answers

Answered by Anonymous
2

Answer:

A cottage industry produces a certain number of pottery articles in a

day. It was observed on a particular day that the cost of production of

each article (in rupees) was 3 more than twice the number of articles

produced on that day. If the total cost of production on that day was `

90, find the number of articles produced and the cost of each article

Answered by HippySunshine
4

Answer:

Let there be x articles.

Then the production cost of each article=3+2x

Total production cost x(3x+2x)=90

3x^2+2x^2=90

2x^2+3x-90=0

2x^2+15x-12x-90=0

2x(x-6)+15(x-6)=0

(2x+15)(x-6)=0

x=6,-15/2

Number cannot be negative

So,number of articles=6 and the cost of each articles=Rs.15.

Hope it helps you

THANKS!!

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