A cottage industry produces a certain number of pottery articles in a day .It was observed that on a particular day that the cost of production of each article was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs90, find the number of articles produced and the cost of each article?
Answers
Answered by
1
Step-by-step explanation:
production
A.T.Q
90.= x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x+15=0 ⇒2x= - 15
⇒x= -15/2
⇒x – 6 = 0
⇒x=6
⇒ x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6.
Hence, number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15.
--------------------------------------------------------------------------------------------------
Answered by
0
Answer:
52
Step-by-step explanation:
Similar questions