Question

a cottage industry produces a certain number of pottery articles in day. it was obserbe tha on a particular day that the cost of production of each article (in rupees) was three more than twice the number of article produced on that day.

Answer 1

Let the no. of article be x.Thenthe cost of each article be 2x+3.A/Q,   x(2x+3)=90   2x2+3x=90    2x2+3x-90=0   2x2+15x-12x-90=0   x(2x+15)-6(2x+15)=0   (x-6)=0 & (2x+15)=0   => x=6 & x= -15/2So,The no. of each article is 6 and the cost of each article is 2x6+3=15.                                                                                                            Proved....

Answer 2

The totɑl cost of production= Rs.90

Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)      

the totɑl cost of production = no. of  pottery ɑrticles produced × cost of production

ɑ.T.Q

90.= x(2x + 3) = 0

⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0

Now 2x+15=0 ⇒2x= - 15

⇒x= -15/2


 ⇒x – 6 = 0

⇒x=6

⇒ x = -15/2 or x = 6

ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.


Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.

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