Question

a cottage industry produces a certain number of pottery articles in a day.it was observed on a particular day that cost of production of each article was 3 more than twice the number of articles produced on that day if the total cost of production on that day was rupees 90,find the number of articles produced and the cost of each article.

Answer 1

Answer:

$answer$

Let the total number articles be x

ACQ,

We have cost of production of each article on a particular day was 3 more than twice the number of articles produced on that day .

Then the production cost of each article = 3 +2x

Also the total cost of production on that day was Rs 90

Total cost of production on that day = x ( 3 + 2x)

= 90

$= > 3x + {2x}^{2} = 90 \\ = > {2x}^{2} + 3x - 90 = 0 \\ = > {2x}^{2} + 3x - 12x - 90 = 0 \\ = > x (2x + 15) \: (x - 5) = 0 \\ so \: x = \frac{ - 15}{2} .6$

number of articles can never be negative so we don't consider -15/2

number of articles produced is 6

Cost of each article = 3 + 2x

=3 + 2 × 6

= 15 articles

Therefore,the number of articles is 15

and the cost of each article is RS 6

Hope it helps you

Answer 2

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.