a cottage industry produces a certain number of pottery articles in a day. it was observed on a particular day that the cost of production of each articles( in rupees) was 3 more than twice the number of articles produced on that day . If the total cost of production on that day watch rupees 90, find the number of articles produced and cost of each article.
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☜☆☞hey dear friend ☜☆☞
here is your answer ☞
_________
Let the number of articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
It is given that the total production is Rs 90.
=> x(2x+3) = 90
=> 2x²+3x=90
=> 2x²+3x-90=0
=> 2x²+15x-12x-90=0
=> x(2x+15)-6(2x+15)=0
=> (x-6)(2x+15)=0
Either 2x + 15 = 0 or x − 6 = 0, i.e., x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6.
Hence, number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15
I think my answer is capable to clear your confusion
Devil_king ▄︻̷̿┻̿═━一
here is your answer ☞
_________
Let the number of articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
It is given that the total production is Rs 90.
=> x(2x+3) = 90
=> 2x²+3x=90
=> 2x²+3x-90=0
=> 2x²+15x-12x-90=0
=> x(2x+15)-6(2x+15)=0
=> (x-6)(2x+15)=0
Either 2x + 15 = 0 or x − 6 = 0, i.e., x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6.
Hence, number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15
I think my answer is capable to clear your confusion
Devil_king ▄︻̷̿┻̿═━一
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0
The totɑl cost of production= Rs.90
Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)
the totɑl cost of production = no. of pottery ɑrticles produced × cost of production
ɑ.T.Q
90.= x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x+15=0 ⇒2x= - 15
⇒x= -15/2
⇒x – 6 = 0
⇒x=6
⇒ x = -15/2 or x = 6
ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.
Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.
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Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)
the totɑl cost of production = no. of pottery ɑrticles produced × cost of production
ɑ.T.Q
90.= x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x+15=0 ⇒2x= - 15
⇒x= -15/2
⇒x – 6 = 0
⇒x=6
⇒ x = -15/2 or x = 6
ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.
Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.
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