Question

a cottage industry produces a certain number of pottery articles in a day. it was observed on a particular day that the cost of production of each articles( in rupees) was 3 more than twice the number of articles produced on that day . If the total cost of production on that day watch rupees 90, find the number of articles produced and cost of each article.

Answer 1

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here is your answer ☞
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Let the number of articles produced be x.

Therefore, cost of production of each article = Rs (2x + 3)

It is given that the total production is Rs 90.

=> x(2x+3) = 90

=> 2x²+3x=90

=> 2x²+3x-90=0

=> 2x²+15x-12x-90=0

=> x(2x+15)-6(2x+15)=0

=> (x-6)(2x+15)=0


Either 2x + 15 = 0 or x − 6 = 0, i.e., x = -15/2  or x = 6

As the number of articles produced can only be a positive integer, therefore, x can only be 6.

Hence, number of articles produced = 6

Cost of each article = 2 × 6 + 3 = Rs 15

I think my answer is capable to clear your confusion

Devil_king ▄︻̷̿┻̿═━一

Answer 2

The totɑl cost of production= Rs.90

Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)      

the totɑl cost of production = no. of  pottery ɑrticles produced × cost of production

ɑ.T.Q

90.= x(2x + 3) = 0

⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0

Now 2x+15=0 ⇒2x= - 15

⇒x= -15/2


 ⇒x – 6 = 0

⇒x=6

⇒ x = -15/2 or x = 6

ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.


Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.

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