Question

A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs.90, find the number of articles produced and the cost each article.



No copied answers.

Hoping for a Great answer.

$\large \bigstar{ \underline{ \underline{ { \boxed{ \frak \pink{Thank \: you}}}}}} \bigstar$
​

Answer 1

${\huge\boxed{\red{ \boxed{ \pink{hope \: it \: helps}}}}} \\ \\ {\huge\boxed{\pink{ \boxed{ \red{pls \: mark \: as \: brainleist}}}}}$

Answer 2

Answer:

Let the number of articles produced be x.

Therefore, cost of production of each article =Rs. (2x+3)

It is given that the total production is Rs. 90.

∴x(2x+3)=90

⇒2x2+3x−90=0

⇒2x2+15x−12x−90=0

(Splitting the middle term 3x as 15x−12x because 15x×−12x=−180x2)

⇒x(2x+15)−6(2x+15)=0

⇒(2x+15)(x−6)=0

Either, 2x+15=0 or x−6=0

⇒x=−152 or x=6

As the number of articles produced can only be a positive integer, so x can only be 6.

Hence, number of articles produced = 6

Cost of each article = 2×6+3=Rs 15