Math, asked by mdalifiroz3, 1 day ago

A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced and the cost of each article.​

Answers

Answered by singhraj182008
2

Step-by-step explanation:

Let there be x articles.

Then the production cost of each article =3+2x

Total production cost =x(3+2x)=90

3x+2x2=902x2+3x−90=02x2+15x−12x−90=02x(x−6)+15(x−6)=0(2x+15)(x−6)=0x=6,−215

Number cannot be negative.  

So, number of articles =6 and the cost of each article =Rs.15 

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