Math, asked by Advancebrainly, 1 month ago

A cottage industry produces a certain number of toys in a day.The cost of production of each toy(in rs) was found to be 55 minus the no of toys produced in a day.On a particular day, the total cost of production was rs.750.Find out the no of toys produced on that day.​

Answers

Answered by Popxgirl
111

Refer the above attachment :)

-@PinkiMeena...~

Attachments:
Answered by CᴀᴘᴛᴀìɴLᴇᴠí
17

 \bf {\huge{ \underline{ \underline{ \red{ Aɴsᴡᴇʀ}}}}}

  • Let the number of toys produced on that day = x

  • Cost of production of each toy that day =55−x

  • On a particular day, total cost of production was 750

 \begin{gathered} \sf⟹ \: x(50 −x)=750  \:  \:  \:  \:  \:  \:  \: \\  \sf⟹x2−55x+750=0 \:  \\ \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  ⟹x2−30x−25x+750=0 \\ \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ⟹x(x−30)−25(x−30)=0 \\ \\ \sf⟹x=25,30 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \end{gathered}

\therefore{ \small{ \boxed{ \underline{ \pink{ \sf{Maximum \:  number  \: of \:  toys \:  produced \:  that \:  day =30}}}}}}

Similar questions