A cottage industry produces a certain number of wooden toys in a day . The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day . On a particular day , the total cost of production was ₹750 . What id the number of toys produced on that day
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LET x BE THE NUMBER OF TOYS PRODUCED ON THAT DAY
ATQ
THE COST OF AN EACH TOYS 55 - x = 750/x
=>55x - x2(X SQUARE) = 750
X2 - 55X + 750 = 0
X2 -(30+25)x + 750= 0(SPLITTING THE MIDDLE TERM)
x2 - 30x - 25x + 750 =0
x(x-30) - 25(x - 30) = 0
(X-30)(X-25) =0
EITHER X=30 OR X=25
HENCE NO. OF TOYS PRODUCED ON THAT DAY IS EITHER 30 OR 25.
HOPE IT HELPS
ATQ
THE COST OF AN EACH TOYS 55 - x = 750/x
=>55x - x2(X SQUARE) = 750
X2 - 55X + 750 = 0
X2 -(30+25)x + 750= 0(SPLITTING THE MIDDLE TERM)
x2 - 30x - 25x + 750 =0
x(x-30) - 25(x - 30) = 0
(X-30)(X-25) =0
EITHER X=30 OR X=25
HENCE NO. OF TOYS PRODUCED ON THAT DAY IS EITHER 30 OR 25.
HOPE IT HELPS
Answered by
11
Hope this helps
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Pls give brainliest because I need just one brainliest to be virtuoso pls bro help me
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Adithya2018:
Sorry balance conclusion is the no of toys can be either 30 or 25
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