A cottage is on a bearing of 200° and 110° from Dogne and Manu farm respectively. If Dogne walked 5km and Manu 3km from the cottage to their farm,find correct to 2sf the distance between the two farms, the nearest degree,the bearing of Manu farm from Dogne farm
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(a) Distance=AB+BC+CD
=(500+400+200)=1100m
(b) Displacement=AD=(AB−CD)2+BC2−−−−−−−−−−−−−−−−√
=(500−200)2+(400)2−−−−−−−−−−−−−−−−−√
=500m
(c) Average speed=Total distanceTotal time
=110020=55m/min
(d) Average velocity=ADt
=50020=25m/min(alongAD)
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