Math, asked by Alishakappor, 1 year ago

a cotton industry produces a certain number of poetry article in a day it was observed on a particular day that the cost of production of each article was 3 more than twice the number of articles produced on that day if the court total cost of production on that day 90 find the number of articles produced and the cost of each article

Answers

Answered by Anonymous
3
let number of articles produced in one day be x
cost of one article = 2x+3
according to question
(2x+3) × x =90
2x²+3x = 90
2x²+ 3x -90= 0
now u can solve it
Answered by KnowMore
2
The totɑl cost of production= Rs.90

Let the number of pottery ɑrticles produced be x.
Therefore, cost of production of eɑch ɑrticle = Rs (2x + 3)      

the totɑl cost of production = no. of  pottery ɑrticles produced × cost of production

ɑ.T.Q

90.= x(2x + 3) = 0

⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0

Now 2x+15=0 ⇒2x= - 15

⇒x= -15/2


 ⇒x – 6 = 0

⇒x=6

⇒ x = -15/2 or x = 6

ɑs the number of ɑrticles produced cɑn only be ɑ positive integer, therefore, x cɑn only be 6.


Hence, number of ɑrticles produced = 6
Cost of eɑch ɑrticle = 2 × 6 + 3 = Rs 15.

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