A couple of movement 105.N.m acts in the plane of the paper. Let couple 70N forces
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What is the question...
i think ur question is to find the Perpendicular distance of Force from the axis of Rotation..
if that is the Question
then u answer should be.
Torque= F×R(perpendicular distance)
105=70×R
R=105/70
R=10.5/7= 1.5metre
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Answer:
Explanation: mlmlmnmnb ooio
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