Question

A couple with a newborn baby is troubled that the child does not resemble either of them. Suspecting that a mixup occurred at the hospital, they check the blood type of the infant. It is type O. Because the father is type A and the mother type B, they conclude that a mixup has definitely occurred. Are they correct? Give reason for your answer.

Answer 1

Answer:

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Answer 2

Then parents are incorrect.

Explanation:

• The father of the newborn has blood group A.
• He can be homozygous for the A allele, that is, his genotype can be A/A or heterozygous for the A allele, that is , his genotype can be A/i.
• The mother of the newborn has blood group B.
• She can be homozygous for the B allele, that is, her genotype can be B/B or heterozygous for the B allele, that is , her genotype can be B/i.
• If both parents show heterozygosity, that is, they have the genotypes, A/i and B/i respectively, then their cross will be as follows :

                                     A           i

                       B         A/B         B/i

                                  (AB)        (B)

                        i         A/i           i/i

                                  (A)          (O)

• The characters in the brackets () above represents the blood groups.
• In the above cross we can see the possibility of development of offspring with four different types of blood groups, which are, AB, A, B and O respectively.
• Therefore, the infant with O blood group can be the child of the parents.
• The parents are wrong.