a courtard is 4.8 m by 3.2 M is floor is to be constructed with tiles measuring 10 cm x 10 cm find the number of tiles required to cover the floor
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l=4.8m
b= 3.2m
ar.=l×b=>4.8×3.2
ar.2=0.1×0.1
no. of tiles required=ar1÷ar.2
". =4.8×3.2÷0.1×0.1=1536
therefore no. of tiles is 1536
I hope it helps
pls follow
b= 3.2m
ar.=l×b=>4.8×3.2
ar.2=0.1×0.1
no. of tiles required=ar1÷ar.2
". =4.8×3.2÷0.1×0.1=1536
therefore no. of tiles is 1536
I hope it helps
pls follow
Answered by
0
Answer:
Step-by-step explanation:frist we perimeter the floor
4.8×3.2
=153.6
& Perimeter of the tile=10×10
=
They cover cm of the floor.
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