A courtyard 20m long and 15m broad is to be paved with bricks of length 25cm and breadth 12m find number of bricks
nano101:
its 1000 bricks i think
Answers
Answered by
80
Length of court yard = 20m
breadth = 15 m
area = l×b = 20×15 = 300m² = 300×10000 cm²
length of a brick = 25cm
breadth = 12cm
area of a brick = 25×12 = 300 cm²
number of bricks = (area of courtyard)/(area of a brick)
= (300×10000)/(300)
= 10000 bricks
breadth = 15 m
area = l×b = 20×15 = 300m² = 300×10000 cm²
length of a brick = 25cm
breadth = 12cm
area of a brick = 25×12 = 300 cm²
number of bricks = (area of courtyard)/(area of a brick)
= (300×10000)/(300)
= 10000 bricks
Answered by
54
Very simple!!
Length of courtyard=20 m=2000 cm
Breadth of courtyard=15 m=1500 cm
So,area of courtyard=(2000x1500) cm²
Length of a brick=25 cm
Breadth of a brick=12 cm
So,area of a brick=(25x12) cm²
So,number of bricks required=(2000x1500)/(25x12)=10,000 bricks
So,total bricks required to pave the courtyard=10,000 bricks
Length of courtyard=20 m=2000 cm
Breadth of courtyard=15 m=1500 cm
So,area of courtyard=(2000x1500) cm²
Length of a brick=25 cm
Breadth of a brick=12 cm
So,area of a brick=(25x12) cm²
So,number of bricks required=(2000x1500)/(25x12)=10,000 bricks
So,total bricks required to pave the courtyard=10,000 bricks
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