Question

A courtyard, 25 m long and 16 m broad, is to be laid with bricks of length 20 cm and
10 cm. Find the number of bricks required.​

Answer 1

$\tiny \bf No. \: \: of \: \: bricks \: \: required = \frac{Dimension \: of \: courtyard }{Dimension \: of \: bricks} \\ \\ \frak{ \: \: \: \: \: \: \: \: \: \: \: \: = > \frac{25 \times 16}{ \frac{20}{100} \times \frac{10}{100} } } \\ \\ \\ \frak{ \: \: \: \: \: \: \: \: \: \: \: \: = >\frac{25 \times 16}{0.2 \times 0.1} = \frac{400}{0.02} } \\ \\ \frak{ \: \: \: \: \: \: \: \: \: \: \: \:= > \frac{400 \times 100}{2} } \\ \frak { \: \: \: \: \: \: \: \: \: \: \: \: = > 200 \times 100} \\ \frak { \: \: \: \: \: \: \: \: \: \: \: \: = > \red{20000}}$

• Hence, → A courtyard, 25 m long and 16 m broad, when laid with bricks of length 20 cm and 10 cm, would require 20000 bricks in whole.