Math, asked by srinikethan139, 9 months ago

A cover of a laptop measure 45cm.40.30cm.if a cardboard packet contain a maximum of 15 such cover box of laptop find the volume of cardboard packet

Answers

Answered by benjaison2006
5

Answer:

length of box = 45 cm

breadth of box = 40 cm

height of box = 30 cm

volume of the box = l×b×h

= 45×40×30

= 54,000 cm

Volume of 15 such boxes = 15×54,000

= 810,000 cm

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Step-by-step explanation:

Answered by ptl
1

Step-by-step explanation:

LENGTH OF LAPTOP COVER, L= 45cm = 0.45m

BREADTH OF LAPTOP COVER,B=40 cm = 0.40m

HEIGHT OF LAPTOP COVER,H= 30cm = 0.30m

VOLUME OF THE COVER , V= L.B.H

V = 0.45*0.40*0.30

= 0.054

NOW SINCE A CARDBOARD CONATINS 15 SUCH COVERS

V OF CARDBOARD = 15 * V OF COVER

V= 15 *0.054

V = 0.81

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