Question

a covex lens of focal length 25cm and a concave lens of focal length 10cm are placed in close contant wiyh each other calculate the lens
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Answer:

→ FOCAL LENGTH OF COMBINATION ( F ) = [ - 50 / 3 ] cm ←

♒ Nature Of Combination Of Lens = DIVERGING LENS ≈ [ Concave Lens ]

Explanation:

★ RAY OPTICS ★

★ ★ COMBINATION OF LENSES ★ ★

★ GIVEN ;

» Focal length of Convex Lens ( F¹ ) = 25 cm

» Focal length of Concave Lens ( F² ) =-10 cm

★ Focal length of Combination ( F )= ???

______ [ BY USING FORMULA ] _________

[ \frac{1}{f} \: = \: \frac{1}{ {f}^{1} } \: + \: \frac{1}{ {f}^{2} }

f

1

=

f

1

1

+

f

2

1

]

★ 1 / F = 1 / 25 + 1 / -10

» 1 / F = [ ( -10 )+ 25 ] / 25 × ( -10 )

» F = -250 / 15

⏩ » F = [ - 50 / 3 cm ] « ⏪

_______________________________________

ANSWER :- FOCAL LENGTH OF COMBINATION OF LENSES IS ;

[ ★ F = - 50 / 3 cm ★ ]

♣ HENCE ; NATURE OF COMBINATION OF LENS IS "" DIVERGING "" .

» BECAUSE FOCAL LENGTH IS [ NEGATIVE ] .