Question

A cow has four legs if there are x Cos then write the equation for total number of legs x cows

Answer 1

Answer:

Let no. of hens be x and no. of cows be y. For heads the equation is

x + y = 50 (head count is 50)

For legs the equation is

2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)

From head count equation

y = 50 - x

substituting this in leg count equation we get

2x + 4(50 - x) = 144

2x + 200 - 4x = 144

-2x = 144 - 200

-2x = - 56

x = 28

Substituting in headcount equation we get

y = 50 - 28

So y = 22

So there are 28 hens and 22 cows on the farm

Answer 2

Answer:

4x

Step-by-step explanation:

If 1 cow has 4 legs, then the x cows have 4x legs