a cow is sold at a profit of 10%.Had it been sold for RS 930 more, the profit would have been 25%.Find the cost price of the cow
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let the selling price is y
and let the cost of cow is x, then
((y-x) /x)*100=10. equation (1)
(y-x) /x=10/100
now if he sell it 930 rs more then
((930+y-x) /x) *100=25. equation (2)
{[(930/x)+(y-x) ]/x}=25/100
now from equation (1)
{(930/x)+(10/100)}=1/4
930/x=1/4-1/10
930/x=6/40=3/20
x=930*20/3
x=310*20
x=6200rs
therefore the cost of cow is 6200 rs.
and let the cost of cow is x, then
((y-x) /x)*100=10. equation (1)
(y-x) /x=10/100
now if he sell it 930 rs more then
((930+y-x) /x) *100=25. equation (2)
{[(930/x)+(y-x) ]/x}=25/100
now from equation (1)
{(930/x)+(10/100)}=1/4
930/x=1/4-1/10
930/x=6/40=3/20
x=930*20/3
x=310*20
x=6200rs
therefore the cost of cow is 6200 rs.
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