A cow is tied at a point e with a ope of 4 m. E and F are the midpoints of Ad and Gh respectively. Find the amount of area that can be grazed by a cow in m2
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Answer:
Given-ABCD is a rectangular field of dimensions 20m×16m.
A cow tied by a rope BP=BQ=14m at B, is grazing.
Here the cow grazes an area A = Area of Sector with central angle 90o and radius 14m.
∴A=360oθ×π×r2 where θ= Central Angle =90o,
and
r= radius of the sector=14m.
∴A=360o90o×722×142=154m2.
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