a cow is tied at point e with a rope of 4m e and f are the mid points of ad and gh respectively. find the amount of area that can be grazed by a cow in m^2
Answers
Answer:
Step-by-step explanation:
7th
Maths
Perimeter and Area
Applications of Perimeter and Area of Regular Shapes
A cow is tied with a rope o...
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Asked on January 17, 2020 by
Nilraj Johnson
A cow is tied with a rope of length 14 m at the corner of a rectangular field of dimensions 20m×16m. The area of the field in which the cow can graze is :
MEDIUM
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ANSWER
Given-ABCD is a rectangular field of dimensions 20m×16m.
A cow tied by a rope BP=BQ=14m at B, is grazing.
Here the cow grazes an area A = Area of Sector with central angle 90
o
and radius 14m.
∴A=
360
o
θ
×π×r
2
where θ= Central Angle =90
o
,
and
r= radius of the sector=14m.
∴A=
360
o
90
o
×
7
22
×14
2
=154m
2
.
Given:
Length of the rope - 4m.
To Find:
The area that can be grazed by a cow.
Solution:
We know that,
The area grazed by the cow will be circular.
Considering the length of the rope as the radius of the circle.
Then,
The area of the circle = πr².
The area of the circle = π × 4².
The area of the circle = π × 16.
The area of the circle = 50.26 m².
Hence, the amount of area that can be grazed by a cow in m² is 50.26 m².