Question

A cow is tied on the corner of a rectangular field of size 30m× 20m by a 14 m long rope the area of the region, that it can graze, is(useπ=22\7)​

Answer 1

♥️consider the area as a♥️ quadrant of circle then♥️

♥️Area grazed by cow♥️

♥️=0/360×πr^2♥️

♥️=>90/360×22/7×40×40♥️

♥️=>22×10×40/7♥️

♥️=>8800/7♥️

♥️=>1257.143 m^2♥️

♥️♥️Mark as brainlist♥️♥️

Answer 2

The area of the region, that it can graze is  $154 m^2$

Step-by-step explanation:

Length of field = 30 m

Breadth of filed = 20 m

We are given that A cow is tied on the corner of a rectangular field of size 30m× 20m by a 14 m long rope

So, Length of rope = 14 m

All angles of rectangle is 90°

So, The angle of sector formed by grazing of cow must be 90°

So, Radius of sector = 14 m

Area of sector = $\frac{\theta}{360^{\circ}} \pi r^2$

Area of sector = $\frac{90^{\circ}}{360^{\circ}} \times \frac{22}{7} \times 14^2$

Area of sector =$154 m^2$

Hence  the area of the region, that it can graze is  $154 m^2$

#learn more :

A cow is tied with a rope of lenght 14 m at the corner of a rectangular field of dimensions 20 m × 16 m . Find the area of the field in which the cow can graze.

https://brainly.in/question/8610272