a cow is tied to the base of a pole with a 11 m long rope the cow moves keeping the rope tight find the area of the ground swepty by the rope in one complete rotation of the cow
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half partof circle is called semicircle
jaybhan1982:
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Answer:
379.94 m^2
Step-by-step explanation:
radius of the circle = 11m (given)
area = π × (radius)^2
= 3.14 × 11^2
= 3.14 × 121
= 379.94 m^2
alternative solution
area = π × 11^2
= 121π m^2
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