Question

A cow is tied with a rope of 7m. The grass grazed field by the cow​

Answer 1

Answer:

The area of field that cow can graze is

$a = \pi {(7m)}^{2} \\ \\ \to \: a = \frac{22}{ \cancel7} \times \cancel7 \times 7 \\ \\ = 22 \times 7 {m}^{2} \\ \\ = {154m}^{2}$

Hope it helps you from my side

Answer 2

Answer:

ARE YOU

IGNORING ME T.T

BUT WHYYYYYY DID I DID SOMETHING TO YOU:(

DID I HURT YOU

Step-by-step explanation:

The area of the field in which the cow cannot graze is 281.5 m^2281.5m2

Step-by-step explanation:

A cow is tied with a rope of length 7 m at a corner of a rectangular field

All angles of rectangle are 90°

Length of rope = 7 m

Area of sector that cow can graze =\frac{\theta}{360} \pi r^2 = \frac{90}{360} \times \frac{22}{7} 7^2 =38.5 m^2360θπr2=36090×72272=38.5m2

Length of rectangular field = 20 m

Breadth of rectangular field = 16 m

Area of field =Length \times Breadth = 20 \times 16 = 320 m^2Length×Breadth=20×16=320m2

The area of the field in which the cow cannot graze = 320 - 38.5 = 281.5 m^2320−38.5=281.5m2

Hence The area of the field in which the cow cannot graze is 281.5 m^2

A cow is tied with rope of length 3.5m at corner of a rectangular field of dimensions 22m×15m .Find the area of the field in which cow can graze and in which she cannot graze.