A cow of weighing 160 kgf stands on foot each of area of cross section (4) 4 cm2 on the floor. An elephant weighing 2000 kgf stands on foot each of area of cross section 250 cm2 . Compare the pressure exerted by them.
Answers
Answered by
1
Answer:
1.25
Explanation:
pressure=Force ÷ area
p1 is pressure of cow p2 is pressure of elephant
p1=F÷a² =mg÷a²= 160×9.8=98N/m² ....1
p2=F÷a²=mg÷a²=2000×9.8=78.4N/m² ...2
from equation 1 and 2
p1/p2=98/78.4=1.25
Similar questions