Question

A cow tied with rope of length 28m at the corner of rectangular field of dimension 40m X 32m them the area of the field in which cow can graze

Answer 1

ANSWER IS IN THE ATTACHMENT!

Answer 2

$\mathcal{\huge{\fbox{\purple{Solution:-}}}}$

▶Area of the field in which the cow can graze

= πr²/4

= π(28)²/4

= 784π/4

= 196π

= 196 ×22/7 

= 615.45 m²

▶ Area of rectangular field

= l × b

= 40 × 32

= 1280 m²

Area of the field in which the cow cannot graze

= Area of rectangular field - Area of the field in which the cow can graze

= 1280 m² - 615.45 m²

= 664.55 m².  

___________________________________