Question

A cow worth 9000 is sold by A to B at 10% loss. B sells
the cow back to A at 10% gain. Who losses?​

Answer 1

Step-by-step explanation:

->A sold the cow to B at 10% loss

So, the value in which A sold the cow is:-

-> 9000 - {9000×(10÷100)} $

= 9000 - {9000 ×(1÷10)}$

=9000 - 900 $ = 8100 $

Now the value of cow is 8100 $

-> Then B sold the cow to A at 10% gain

So,the value in which B sold the cow is:-

-> 8100 + {8100×(10÷100) $

=8100 + 810 $ =8910 $

A lost more, because at first he losses 900 rs. Then he bought the cow with 90 rs. gain.

So A losses total 810 rs.

But B gain total 810 rs.

So here A losses more.

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