A cracker rocket is ejecting gases at a rate of 0.05kg per/sec with a velocity 400 m per/sec . Find the acceleration force on the rocket
Ankitgodara53:
hi
Answers
Answered by
16
heya di
The answer of ur question is
Ejecting gas at 0.05 kg per sec
velocity =400 m per /sec
so dm /dt = 0.05
F = V × dm /dt
= 400 × 0.05
=20 Newton
hope it helps
The answer of ur question is
Ejecting gas at 0.05 kg per sec
velocity =400 m per /sec
so dm /dt = 0.05
F = V × dm /dt
= 400 × 0.05
=20 Newton
hope it helps
Answered by
27
Hey mate ^_^
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Answer:
=======
Momentum of the ejection gases = mass × velocity
=0.05 × 400
=20kgm/s
=20N
Hence the acceleration force of the rocket is 20 N
#Be Brainly❤️
=======
Answer:
=======
Momentum of the ejection gases = mass × velocity
=0.05 × 400
=20kgm/s
=20N
Hence the acceleration force of the rocket is 20 N
#Be Brainly❤️
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