Physics, asked by Shanaya200, 1 year ago

A cracker rocket is ejecting gases at a rate of 0.05kg per/sec with a velocity 400 m per/sec . Find the acceleration force on the rocket


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Answers

Answered by limelight1726
16
heya di

The answer of ur question is

Ejecting gas at 0.05 kg per sec
velocity =400 m per /sec

so dm /dt = 0.05

F = V × dm /dt
= 400 × 0.05
=20 Newton


hope it helps

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Answered by Anonymous
27
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Answer:
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Momentum of the ejection gases = mass × velocity

           =0.05 × 400

           =20kgm/s

           =20N

Hence the acceleration force of the rocket is 20 N


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